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Popular >

y^'=y^2(5+x)

Solution

y^{^{'}} = y^{2} (5 + x)

Solution

y = - \frac{2}{10 x + x ^{2} + c _{1}}

Solution steps

y^{'} (x) = y^{2} (5 + x)

Solve separable ODE:

y = - \frac{2}{10 x + x ^{2} + c _{1}}

y = - \frac{2}{10 x + x ^{2} + c _{1}}

Popular Examples

(\partial)/(\partial x)(z/(1+z^2y^2))

\frac{\partial}{\partial x} (\frac{z}{1 + z ^{2} y ^{2}})

derivative of Axe^{3x}

\frac{d}{d x} (A x e^{3 x})

f(t)=sin(t)-tcos(t)

f (t) = sin (t) - t cos (t)

f^'(x)=(1-e^x)/(9+e^x)

f^{^{'}} (x) = \frac{1 - e ^{x}}{9 + e ^{x}}

xy^'+y=-2xy^2,y(1)=2

x y^{^{'}} + y = - 2 x y^{2}, y (1) = 2

Frequently Asked Questions (FAQ)

What is the solution for y^'=y^2(5+x) ?
The solution for y^'=y^2(5+x) is y=-2/(10x+x^2+c_{1)}