What is the integral of (x)^{1/3} ?

The integral of (x)^{1/3} is 3/4 x^{4/3}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (x)^{1/3}

\int (x)^{\frac{1}{3}} d x

\frac{3}{4} x^{\frac{4}{3}} + C

Solution steps

\int x^{\frac{1}{3}} d x

Apply the Power Rule

: \frac{3}{4} x^{\frac{4}{3}}

= \frac{3}{4} x^{\frac{4}{3}}

Add a constant to the solution

= \frac{3}{4} x^{\frac{4}{3}} + C

\int \frac{5}{3} x d x

\int sin (2 t) sin (t) d t

\int \frac{e ^{2 x}}{8 + e ^{2 x}} d x

\int \frac{1}{( 1 + x ) ^{\frac{7}{2}}} d x

\int (3 x^{2} - 8 x) e^{2 x} d x