What is the integral of (9x^8-2x-6) ?

The integral of (9x^8-2x-6) is x^9-x^2-6x+C

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integral of (9x^8-2x-6)

\int (9 x^{8} - 2 x - 6) d x

x^{9} - x^{2} - 6 x + C

Solution steps

\int 9 x^{8} - 2 x - 6 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 9 x^{8} d x - \int 2 x d x - \int 6 d x

\int 9 x^{8} d x = x^{9}

\int 2 x d x = x^{2}

\int 6 d x = 6 x

= x^{9} - x^{2} - 6 x

Add a constant to the solution

= x^{9} - x^{2} - 6 x + C

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What is the integral of (9x^8-2x-6) ?
The integral of (9x^8-2x-6) is x^9-x^2-6x+C