What is the integral of cot^2(u) ?

The integral of cot^2(u) is -u-cot(u)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of cot^2(u)

\int cot^{2} (u) d u

- u - cot (u) + C

Solution steps

\int cot^{2} (u) d u

Rewrite using trig identities

= \int - 1 + csc^{2} (u) d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int 1 d u + \int csc^{2} (u) d u

\int 1 d u = u

\int csc^{2} (u) d u = - cot (u)

= - u - cot (u)

Add a constant to the solution

= - u - cot (u) + C

\int (z + 6) e^{4 z} d z

\int \frac{4 x}{4 - x ^{2}} d x

\int \frac{x ^{2} + 76}{x ^{2} + 81} d x

\int x e^{4} x d x

\int \frac{1}{x ^{2} + x + 3} d x