What is the integral of (6x+11)/((x+1)^2) ?

The integral of (6x+11)/((x+1)^2) is 6ln|x+1|-5/(x+1)+C

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integral of (6x+11)/((x+1)^2)

\int \frac{6 x + 11}{( x + 1 ) ^{2}} d x

6 ln ∣ x + 1 ∣ - \frac{5}{x + 1} + C

Solution steps

\int \frac{6 x + 11}{( x + 1 ) ^{2}} d x

Expand

\frac{6 x + 11}{( x + 1 ) ^{2}} : \frac{6 x}{( x + 1 ) ^{2}} + \frac{11}{( x + 1 ) ^{2}}

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{6 x}{( x + 1 ) ^{2}} d x + \int \frac{11}{( x + 1 ) ^{2}} d x

\int \frac{6 x}{( x + 1 ) ^{2}} d x = 6 (ln ∣ x + 1 ∣ + \frac{1}{x + 1})

\int \frac{11}{( x + 1 ) ^{2}} d x = - \frac{11}{x + 1}

= 6 (ln ∣ x + 1 ∣ + \frac{1}{x + 1}) - \frac{11}{x + 1}

Simplify

6 (ln ∣ x + 1 ∣ + \frac{1}{x + 1}) - \frac{11}{x + 1} : 6 ln ∣ x + 1 ∣ - \frac{5}{x + 1}

= 6 ln ∣ x + 1 ∣ - \frac{5}{x + 1}

Add a constant to the solution

= 6 ln ∣ x + 1 ∣ - \frac{5}{x + 1} + C

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What is the integral of (6x+11)/((x+1)^2) ?
The integral of (6x+11)/((x+1)^2) is 6ln|x+1|-5/(x+1)+C