What is the integral of-(24)/(x^{25)} ?

The integral of-(24)/(x^{25)} is 1/(x^{24)}+C

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integral of-(24)/(x^{25)}

\int - \frac{24}{x ^{25}} d x

\frac{1}{x ^{24}} + C

Solution steps

\int - \frac{24}{x ^{25}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 24 \cdot \int \frac{1}{x ^{25}} d x

Apply the Power Rule

: - \frac{1}{24 x ^{24}}

= - 24 (- \frac{1}{24 x ^{24}})

Simplify

- 24 (- \frac{1}{24 x ^{24}}) : \frac{1}{x ^{24}}

= \frac{1}{x ^{24}}

Add a constant to the solution

= \frac{1}{x ^{24}} + C

\int r^{2} + 1 d r

\int \frac{- 3}{( x - 1 ) ^{2}} d x

\int - \frac{1}{sin ^{2} ( x )} d x

\int \frac{( 4 + x ^{2} )}{x} d x

What is the integral of-(24)/(x^{25)} ?
The integral of-(24)/(x^{25)} is 1/(x^{24)}+C