What is the integral of-1/(sin^2(x)) ?

The integral of-1/(sin^2(x)) is cot(x)+C

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integral of-1/(sin^2(x))

\int - \frac{1}{sin ^{2} ( x )} d x

cot (x) + C

Solution steps

\int - \frac{1}{sin ^{2} ( x )} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int \frac{1}{sin ^{2} ( x )} d x

Use the common integral:

\int \frac{1}{sin ^{2} ( x )} d x = - cot (x)

= - (- cot (x))

Simplify

= cot (x)

Add a constant to the solution

= cot (x) + C

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