What is the integral of (x^{3/2})/2 ?

The integral of (x^{3/2})/2 is 1/5 x^{5/2}+C

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integral of (x^{3/2})/2

\int \frac{x ^{\frac{3}{2}}}{2} d x

\frac{1}{5} x^{\frac{5}{2}} + C

Solution steps

\int \frac{x ^{\frac{3}{2}}}{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int x^{\frac{3}{2}} d x

Apply the Power Rule

: \frac{2}{5} x^{\frac{5}{2}}

= \frac{1}{2} \cdot \frac{2}{5} x^{\frac{5}{2}}

Simplify

\frac{1}{2} \cdot \frac{2}{5} x^{\frac{5}{2}} : \frac{1}{5} x^{\frac{5}{2}}

= \frac{1}{5} x^{\frac{5}{2}}

Add a constant to the solution

= \frac{1}{5} x^{\frac{5}{2}} + C

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What is the integral of (x^{3/2})/2 ?
The integral of (x^{3/2})/2 is 1/5 x^{5/2}+C