What is the integral of (x+1)cos(nx) ?

The integral of (x+1)cos(nx) is 1/n sin(nx)(x+1)+1/(n^2)cos(nx)+C

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integral of (x+1)cos(nx)

\int (x + 1) cos (n x) d x

\frac{1}{n} sin (n x) (x + 1) + \frac{1}{n ^{2}} cos (n x) + C

Solution steps

\int (x + 1) cos (n x) d x

Apply Integration By Parts

: \frac{1}{n} sin (n x) (x + 1) - \int \frac{1}{n} sin (n x) d x

= \frac{1}{n} sin (n x) (x + 1) - \int \frac{1}{n} sin (n x) d x

\int \frac{1}{n} sin (n x) d x = - \frac{1}{n ^{2}} cos (n x)

= \frac{1}{n} sin (n x) (x + 1) - (- \frac{1}{n ^{2}} cos (n x))

Simplify

= \frac{1}{n} sin (n x) (x + 1) + \frac{1}{n ^{2}} cos (n x)

Add a constant to the solution

= \frac{1}{n} sin (n x) (x + 1) + \frac{1}{n ^{2}} cos (n x) + C

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What is the integral of (x+1)cos(nx) ?
The integral of (x+1)cos(nx) is 1/n sin(nx)(x+1)+1/(n^2)cos(nx)+C