What is the tangent of f(x)=3arcsin(x),\at x= 1/2 ?

The tangent of f(x)=3arcsin(x),\at x= 1/2 is y=2sqrt(3)x+pi/2-sqrt(3)

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tangent of f(x)=3arcsin(x),\at x= 1/2

tangent of

f (x) = 3 arcsin (x), at x = \frac{1}{2}

y = 23 x + \frac{π}{2} - 3

Solution steps

Find the tangent point:

(\frac{1}{2}, \frac{π}{2})

Find the slope of

f (x) = 3 arcsin (x) : \frac{df ( x )}{d x} = \frac{3}{1 - x ^{2}}

Compute the slope of

f (x) = 3 arcsin (x)

x = \frac{1}{2} : m = 23

Find the line with slope m=

23

and passing through

(\frac{1}{2}, \frac{π}{2}) : y = 23 x + \frac{π}{2} - 3

y = 23 x + \frac{π}{2} - 3

\frac{d}{d x} (a csc (2) (k x))

\int 5 sec^{4} (x) d x

\frac{d}{d x} (r e^{r x})

\frac{d}{d x} (4 (5 - 7 x)^{5})

f (x) = \frac{3}{( x + 1 ) ^{2}}

What is the tangent of f(x)=3arcsin(x),\at x= 1/2 ?
The tangent of f(x)=3arcsin(x),\at x= 1/2 is y=2sqrt(3)x+pi/2-sqrt(3)