What is the integral of 15/64+x/(64) ?

The integral of 15/64+x/(64) is 15/64 x+(x^2)/(128)+C

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integral of 15/64+x/(64)

\int \frac{15}{64} + \frac{x}{64} d x

\frac{15}{64} x + \frac{x ^{2}}{128} + C

Solution steps

\int \frac{15}{64} + \frac{x}{64} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{15}{64} d x + \int \frac{x}{64} d x

\int \frac{15}{64} d x = \frac{15}{64} x

\int \frac{x}{64} d x = \frac{x ^{2}}{128}

= \frac{15}{64} x + \frac{x ^{2}}{128}

Add a constant to the solution

= \frac{15}{64} x + \frac{x ^{2}}{128} + C

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What is the integral of 15/64+x/(64) ?
The integral of 15/64+x/(64) is 15/64 x+(x^2)/(128)+C