What is the integral of (3/(2w^3)-(3w^2)/5) ?

The integral of (3/(2w^3)-(3w^2)/5) is -3/(4w^2)-(w^3)/5+C

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integral of (3/(2w^3)-(3w^2)/5)

\int (\frac{3}{2 w ^{3}} - \frac{3 w ^{2}}{5}) d w

- \frac{3}{4 w ^{2}} - \frac{w ^{3}}{5} + C

Solution steps

\int \frac{3}{2 w ^{3}} - \frac{3 w ^{2}}{5} d w

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{3}{2 w ^{3}} d w - \int \frac{3 w ^{2}}{5} d w

\int \frac{3}{2 w ^{3}} d w = - \frac{3}{4 w ^{2}}

\int \frac{3 w ^{2}}{5} d w = \frac{w ^{3}}{5}

= - \frac{3}{4 w ^{2}} - \frac{w ^{3}}{5}

Add a constant to the solution

= - \frac{3}{4 w ^{2}} - \frac{w ^{3}}{5} + C

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What is the integral of (3/(2w^3)-(3w^2)/5) ?
The integral of (3/(2w^3)-(3w^2)/5) is -3/(4w^2)-(w^3)/5+C