What is the integral of (10x^4)/(sqrt(1-x^{10))} ?

The integral of (10x^4)/(sqrt(1-x^{10))} is 2arcsin(x^5)+C

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integral of (10x^4)/(sqrt(1-x^{10))}

\int \frac{10 x ^{4}}{1 - x ^{10}} d x

2 arcsin (x^{5}) + C

Solution steps

\int \frac{10 x ^{4}}{1 - x ^{10}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 10 \cdot \int \frac{x ^{4}}{1 - x ^{10}} d x

Apply u-substitution

: \int \frac{1}{5 1 - u ^{2}} d u

= 10 \cdot \int \frac{1}{5 1 - u ^{2}} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 10 \cdot \frac{1}{5} \cdot \int \frac{1}{1 - u ^{2}} d u

Use the common integral:

\int \frac{1}{1 - u ^{2}} d u = arcsin (u)

= 10 \cdot \frac{1}{5} arcsin (u)

Substitute back

u = x^{5}

= 10 \cdot \frac{1}{5} arcsin (x^{5})

Simplify

10 \cdot \frac{1}{5} arcsin (x^{5}) : 2 arcsin (x^{5})

= 2 arcsin (x^{5})

Add a constant to the solution

= 2 arcsin (x^{5}) + C

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What is the integral of (10x^4)/(sqrt(1-x^{10))} ?
The integral of (10x^4)/(sqrt(1-x^{10))} is 2arcsin(x^5)+C