What is the integral of (cos(θ))/(9sin^2(θ)) ?

The integral of (cos(θ))/(9sin^2(θ)) is -1/9 csc(θ)+C

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integral of (cos(θ))/(9sin^2(θ))

\int \frac{cos ( θ )}{9 sin ^{2} ( θ )} d θ

- \frac{1}{9} csc (θ) + C

Solution steps

\int \frac{cos ( θ )}{9 sin ^{2} ( θ )} d θ

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{9} \cdot \int \frac{cos ( θ )}{sin ^{2} ( θ )} d θ

Apply u-substitution

: \int \frac{1}{u ^{2}} d u

= \frac{1}{9} \cdot \int \frac{1}{u ^{2}} d u

Apply the Power Rule

: - \frac{1}{u}

= \frac{1}{9} (- \frac{1}{u})

Substitute back

u = sin (θ)

= \frac{1}{9} (- \frac{1}{sin ( θ )})

Simplify

\frac{1}{9} (- \frac{1}{sin ( θ )}) : - \frac{1}{9} csc (θ)

= - \frac{1}{9} csc (θ)

Add a constant to the solution

= - \frac{1}{9} csc (θ) + C

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What is the integral of (cos(θ))/(9sin^2(θ)) ?
The integral of (cos(θ))/(9sin^2(θ)) is -1/9 csc(θ)+C