What is the integral of sin(x)sec^4(x) ?

The integral of sin(x)sec^4(x) is 1/3 sec^3(x)+C

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integral of sin(x)sec^4(x)

\int sin (x) sec^{4} (x) d x

\frac{1}{3} sec^{3} (x) + C

Solution steps

\int sin (x) sec^{4} (x) d x

Rewrite using trig identities

= \int \frac{tan ( x )}{cos ^{3} ( x )} d x

Use the basic trigonometric identity:

\frac{1}{cos ( x )} = sec (x)

= \int sec^{3} (x) tan (x) d x

Apply u-substitution

: \int \frac{1}{3} d u

= \int \frac{1}{3} d u

Integral of a constant:

\int a d x = a x

= \frac{1}{3} u

Substitute back

u = sec^{3} (x)

= \frac{1}{3} sec^{3} (x)

Add a constant to the solution

= \frac{1}{3} sec^{3} (x) + C

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What is the integral of sin(x)sec^4(x) ?
The integral of sin(x)sec^4(x) is 1/3 sec^3(x)+C