What is the integral of 3xsqrt(x^2-3) ?

The integral of 3xsqrt(x^2-3) is (x^2-3)^{3/2}+C

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integral of 3xsqrt(x^2-3)

\int 3 x x^{2} - 3 d x

(x^{2} - 3)^{\frac{3}{2}} + C

Solution steps

\int 3 x x^{2} - 3 d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int x x^{2} - 3 d x

Apply u-substitution

: \int u^{2} d u

= 3 \cdot \int u^{2} d u

Apply the Power Rule

: \frac{u ^{3}}{3}

= 3 \cdot \frac{u ^{3}}{3}

Substitute back

u = x^{2} - 3

= 3 \cdot \frac{( x ^{2} - 3 ) ^{3}}{3}

Simplify

3 \cdot \frac{( x ^{2} - 3 ) ^{3}}{3} : (x^{2} - 3)^{\frac{3}{2}}

= (x^{2} - 3)^{\frac{3}{2}}

Add a constant to the solution

= (x^{2} - 3)^{\frac{3}{2}} + C

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What is the integral of 3xsqrt(x^2-3) ?
The integral of 3xsqrt(x^2-3) is (x^2-3)^{3/2}+C