What is the integral of 0.048x+0.95 ?

The integral of 0.048x+0.95 is 0.024x^2+0.95x+C

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integral of 0.048x+0.95

\int 0.048 x + 0.95 d x

0.024 x^{2} + 0.95 x + C

Solution steps

\int 0.048 x + 0.95 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 0.048 x d x + \int 0.95 d x

\int 0.048 x d x = 0.024 x^{2}

\int 0.95 d x = 0.95 x

= 0.024 x^{2} + 0.95 x

Add a constant to the solution

= 0.024 x^{2} + 0.95 x + C

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What is the integral of 0.048x+0.95 ?
The integral of 0.048x+0.95 is 0.024x^2+0.95x+C