What is the integral of 1-2sin^2(x) ?

The integral of 1-2sin^2(x) is 1/2 sin(2x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 1-2sin^2(x)

\int 1 - 2 sin^{2} (x) d x

\frac{1}{2} sin (2 x) + C

Solution steps

\int 1 - 2 sin^{2} (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 1 d x - \int 2 sin^{2} (x) d x

\int 1 d x = x

\int 2 sin^{2} (x) d x = x - \frac{1}{2} sin (2 x)

= x - (x - \frac{1}{2} sin (2 x))

Simplify

= \frac{1}{2} sin (2 x)

Add a constant to the solution

= \frac{1}{2} sin (2 x) + C

\int e^{- 2 x} (1 + x^{2}) d x

\int \frac{6 x + 6}{x ( x - 1 )} d x

\int \frac{2}{csc ( x )} + sec^{2} (x) d x

\int \frac{3 x}{( x - 9 ) ^{2}} d x

\int (sin (x^{2})) x d x

What is the integral of 1-2sin^2(x) ?
The integral of 1-2sin^2(x) is 1/2 sin(2x)+C