What is the integral of y^{(-1)/2} ?

The integral of y^{(-1)/2} is 2y^{1/2}+C

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integral of y^{(-1)/2}

\int y^{\frac{- 1}{2}} d y

2 y^{\frac{1}{2}} + C

Solution steps

\int y^{\frac{- 1}{2}} d y

Apply the Power Rule

: 2 y^{\frac{1}{2}}

= 2 y^{\frac{1}{2}}

Add a constant to the solution

= 2 y^{\frac{1}{2}} + C

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