What is the integral of (2x^2+3)/(x^2sqrt(4-x^2)) ?

The integral of (2x^2+3)/(x^2sqrt(4-x^2)) is 2arcsin(1/2 x)-(3sqrt(4-x^2))/(4x)+C

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integral of (2x^2+3)/(x^2sqrt(4-x^2))

\int \frac{2 x ^{2} + 3}{x ^{2} 4 - x ^{2}} d x

2 arcsin (\frac{1}{2} x) - \frac{3 4 - x ^{2}}{4 x} + C

Solution steps

\int \frac{2 x ^{2} + 3}{x ^{2} 4 - x ^{2}} d x

Expand

\frac{2 x ^{2} + 3}{x ^{2} 4 - x ^{2}} : \frac{2}{4 - x ^{2}} + \frac{3}{x ^{2} 4 - x ^{2}}

= \int \frac{2}{4 - x ^{2}} + \frac{3}{x ^{2} 4 - x ^{2}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{2}{4 - x ^{2}} d x + \int \frac{3}{x ^{2} 4 - x ^{2}} d x

\int \frac{2}{4 - x ^{2}} d x = 2 arcsin (\frac{1}{2} x)

\int \frac{3}{x ^{2} 4 - x ^{2}} d x = - \frac{3 4 - x ^{2}}{4 x}

= 2 arcsin (\frac{1}{2} x) - \frac{3 4 - x ^{2}}{4 x}

Add a constant to the solution

= 2 arcsin (\frac{1}{2} x) - \frac{3 4 - x ^{2}}{4 x} + C

2 x^{- 1}

\int \frac{x + 2}{7 - 9 x ^{2}} d x

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What is the integral of (2x^2+3)/(x^2sqrt(4-x^2)) ?
The integral of (2x^2+3)/(x^2sqrt(4-x^2)) is 2arcsin(1/2 x)-(3sqrt(4-x^2))/(4x)+C