What is the integral from 0 to 4 of 3/64 x^2 ?

The integral from 0 to 4 of 3/64 x^2 is 1

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integral from 0 to 4 of 3/64 x^2

\int_{0}^{4} \frac{3}{64} x^{2} d x

1

Solution steps

\int_{0}^{4} \frac{3}{64} x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{3}{64} \cdot \int_{0}^{4} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{0}^{4}

= \frac{3}{64} [\frac{x ^{3}}{3}]_{0}^{4}

Compute the boundaries:

\frac{64}{3}

= \frac{3}{64} \cdot \frac{64}{3}

Simplify

= 1

\frac{1}{4} y^{^{''}} + 4 y = 2 tan (4 t)

x \to 6 - lim (ln (x - 6))

sin (1 + x^{2})

\frac{d}{d x} (sec^{3} (4 x))

cos (t + \frac{π}{5})

What is the integral from 0 to 4 of 3/64 x^2 ?
The integral from 0 to 4 of 3/64 x^2 is 1