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Popular >

derivative of 3cos(3x+1)

Solution

\frac{d}{d x} (3 cos (3 x + 1))

Solution

- 9 sin (3 x + 1)

Solution steps

\frac{d}{d x} (3 cos (3 x + 1))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (cos (3 x + 1))

Apply the chain rule:

- sin (3 x + 1) \frac{d}{d x} (3 x + 1)

= - sin (3 x + 1) \frac{d}{d x} (3 x + 1)

\frac{d}{d x} (3 x + 1) = 3

= 3 (- sin (3 x + 1) \cdot 3)

Simplify

= - 9 sin (3 x + 1)

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(\partial)/(\partial u)(b((((Nu))/(V(u)))^{(2/3)}))

\frac{\partial}{\partial u} (b ((\frac{( N u )}{V ( u )})^{(\frac{2}{3})}))

integral from 1 to infinity of 1/(x^2)

\int_{1}^{\infty} \frac{1}{x ^{2}} d x

taylor ln(x+1),2 taylor

ln (x + 1), 2

(\partial)/(\partial x)((x^2)/((y-x)^2))

\frac{\partial}{\partial x} (\frac{x ^{2}}{( y - x ) ^{2}})

Frequently Asked Questions (FAQ)

What is the derivative of 3cos(3x+1) ?
The derivative of 3cos(3x+1) is -9sin(3x+1)
What is the first derivative of 3cos(3x+1) ?
The first derivative of 3cos(3x+1) is -9sin(3x+1)