What is the integral of pi^2cos(nx) ?

The integral of pi^2cos(nx) is (pi^2)/n sin(nx)+C

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integral of pi^2cos(nx)

\int π^{2} cos (n x) d x

\frac{π ^{2}}{n} sin (n x) + C

Solution steps

\int π^{2} cos (n x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= π^{2} \cdot \int cos (n x) d x

Apply u-substitution

: \int \frac{cos ( u )}{n} d u

= π^{2} \cdot \int \frac{cos ( u )}{n} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= π^{2} \frac{1}{n} \cdot \int cos (u) d u

Use the common integral:

\int cos (u) d u = sin (u)

= π^{2} \frac{1}{n} sin (u)

Substitute back

u = n x

= π^{2} \frac{1}{n} sin (n x)

Simplify

π^{2} \frac{1}{n} sin (n x) : \frac{π ^{2}}{n} sin (n x)

= \frac{π ^{2}}{n} sin (n x)

Add a constant to the solution

= \frac{π ^{2}}{n} sin (n x) + C

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What is the integral of pi^2cos(nx) ?
The integral of pi^2cos(nx) is (pi^2)/n sin(nx)+C