What is the integral of (3x)/((x+5)^2) ?

The integral of (3x)/((x+5)^2) is 3(ln|x+5|+5/(x+5))+C

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integral of (3x)/((x+5)^2)

\int \frac{3 x}{( x + 5 ) ^{2}} d x

3 (ln ∣ x + 5 ∣ + \frac{5}{x + 5}) + C

Solution steps

\int \frac{3 x}{( x + 5 ) ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int \frac{x}{( x + 5 ) ^{2}} d x

Apply u-substitution

: \int \frac{u - 5}{u ^{2}} d u

= 3 \cdot \int \frac{u - 5}{u ^{2}} d u

Expand

\frac{u - 5}{u ^{2}} : \frac{1}{u} - \frac{5}{u ^{2}}

= 3 \cdot \int \frac{1}{u} - \frac{5}{u ^{2}} d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 3 (\int \frac{1}{u} d u - \int \frac{5}{u ^{2}} d u)

\int \frac{1}{u} d u = ln ∣ u ∣

\int \frac{5}{u ^{2}} d u = - \frac{5}{u}

= 3 (ln ∣ u ∣ - (- \frac{5}{u}))

Substitute back

u = x + 5

= 3 (ln ∣ x + 5 ∣ - (- \frac{5}{x + 5}))

Simplify

= 3 (ln ∣ x + 5 ∣ + \frac{5}{x + 5})

Add a constant to the solution

= 3 (ln ∣ x + 5 ∣ + \frac{5}{x + 5}) + C

\int (- 3 x + 5) cos (2 x) d x

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\int 2 x \cdot x^{2} d x

What is the integral of (3x)/((x+5)^2) ?
The integral of (3x)/((x+5)^2) is 3(ln|x+5|+5/(x+5))+C