What is the integral of \sqrt[a]{x} ?

The integral of \sqrt[a]{x} is (ax^{(1+a)/a})/(1+a)+C

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integral of \sqrt[a]{x}

\frac{a x ^{\frac{1 + a}{a}}}{1 + a} + C

Solution steps

Apply the Power Rule

: \frac{a x ^{\frac{1 + a}{a}}}{1 + a}

= \frac{a x ^{\frac{1 + a}{a}}}{1 + a}

Add a constant to the solution

= \frac{a x ^{\frac{1 + a}{a}}}{1 + a} + C

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What is the integral of \sqrt[a]{x} ?
The integral of \sqrt[a]{x} is (ax^{(1+a)/a})/(1+a)+C