What is the integral of 3e^{1/4 x} ?

The integral of 3e^{1/4 x} is 12e^{1/4 x}+C

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integral of 3e^{1/4 x}

\int 3 e^{\frac{1}{4} x} d x

12 e^{\frac{1}{4} x} + C

Solution steps

\int 3 e^{\frac{1}{4} x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int e^{\frac{1}{4} x} d x

Apply u-substitution

: \int e^{u} \cdot 4 d u

= 3 \cdot \int e^{u} \cdot 4 d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot 4 \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= 3 \cdot 4 e^{u}

Substitute back

u = \frac{1}{4} x

= 3 \cdot 4 e^{\frac{1}{4} x}

Simplify

= 12 e^{\frac{1}{4} x}

Add a constant to the solution

= 12 e^{\frac{1}{4} x} + C

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What is the integral of 3e^{1/4 x} ?
The integral of 3e^{1/4 x} is 12e^{1/4 x}+C