What is the integral of tan^2(x)+sec^2(x) ?

The integral of tan^2(x)+sec^2(x) is -x+2tan(x)+C

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integral of tan^2(x)+sec^2(x)

\int tan^{2} (x) + sec^{2} (x) d x

- x + 2 tan (x) + C

Solution steps

\int tan^{2} (x) + sec^{2} (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int tan^{2} (x) d x + \int sec^{2} (x) d x

\int tan^{2} (x) d x = - x + tan (x)

\int sec^{2} (x) d x = tan (x)

= - x + tan (x) + tan (x)

Simplify

= - x + 2 tan (x)

Add a constant to the solution

= - x + 2 tan (x) + C

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What is the integral of tan^2(x)+sec^2(x) ?
The integral of tan^2(x)+sec^2(x) is -x+2tan(x)+C