What is the integral of (x-3)sin(x) ?

The integral of (x-3)sin(x) is -cos(x)(x-3)+sin(x)+C

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integral of (x-3)sin(x)

\int (x - 3) sin (x) d x

- cos (x) (x - 3) + sin (x) + C

Solution steps

\int (x - 3) sin (x) d x

Apply Integration By Parts

: - cos (x) (x - 3) - \int - cos (x) d x

= - cos (x) (x - 3) - \int - cos (x) d x

\int - cos (x) d x = - sin (x)

= - cos (x) (x - 3) - (- sin (x))

Simplify

= - cos (x) (x - 3) + sin (x)

Add a constant to the solution

= - cos (x) (x - 3) + sin (x) + C

\int (x + 3)^{2} - (x^{2} + 1)^{2} d x

\int \frac{1 + 4 ln ( x )}{x} d x

\int sin (arcsin (x)) d x

\int 4 (1 - x)^{3} d x

\int 2 e^{t} - 3 cos (t) + C d t

What is the integral of (x-3)sin(x) ?
The integral of (x-3)sin(x) is -cos(x)(x-3)+sin(x)+C