What is the integral of 2e^t-3cos(t)+C ?

The integral of 2e^t-3cos(t)+C is 2e^t-3sin(t)+Ct+C

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integral of 2e^t-3cos(t)+C

\int 2 e^{t} - 3 cos (t) + C d t

2 e^{t} - 3 sin (t) + Ct + C

Solution steps

\int 2 e^{t} - 3 cos (t) + C d t

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2 e^{t} d t - \int 3 cos (t) d t + \int C d t

\int 2 e^{t} d t = 2 e^{t}

\int 3 cos (t) d t = 3 sin (t)

\int C d t = Ct

= 2 e^{t} - 3 sin (t) + Ct

Add a constant to the solution

= 2 e^{t} - 3 sin (t) + Ct + C

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What is the integral of 2e^t-3cos(t)+C ?
The integral of 2e^t-3cos(t)+C is 2e^t-3sin(t)+Ct+C