What is the integral of (2x^3-x^2+4)/(x^2) ?

The integral of (2x^3-x^2+4)/(x^2) is x^2-x-4/x+C

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integral of (2x^3-x^2+4)/(x^2)

\int \frac{2 x ^{3} - x ^{2} + 4}{x ^{2}} d x

x^{2} - x - \frac{4}{x} + C

Solution steps

\int \frac{2 x ^{3} - x ^{2} + 4}{x ^{2}} d x

Expand

\frac{2 x ^{3} - x ^{2} + 4}{x ^{2}} : 2 x - 1 + \frac{4}{x ^{2}}

= \int 2 x - 1 + \frac{4}{x ^{2}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2 x d x - \int 1 d x + \int \frac{4}{x ^{2}} d x

\int 2 x d x = x^{2}

\int 1 d x = x

\int \frac{4}{x ^{2}} d x = - \frac{4}{x}

= x^{2} - x - \frac{4}{x}

Add a constant to the solution

= x^{2} - x - \frac{4}{x} + C

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\int 7 arctan (5 y) d y

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What is the integral of (2x^3-x^2+4)/(x^2) ?
The integral of (2x^3-x^2+4)/(x^2) is x^2-x-4/x+C