What is the integral from pi/6 to pi of sin(w) ?

The integral from pi/6 to pi of sin(w) is 1+(sqrt(3))/2

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integral from pi/6 to pi of sin(w)

\int_{\frac{π}{6}}^{π} sin (w) d w

1 + \frac{3}{2}

Decimal

1.86602 \dots

Solution steps

\int_{\frac{π}{6}}^{π} sin (w) d w

Use the common integral:

\int sin (w) d w = - cos (w)

= [- cos (w)]_{\frac{π}{6}}^{π}

Compute the boundaries:

1 + \frac{3}{2}

= 1 + \frac{3}{2}

\int_{0}^{2} 6 x e^{x^{2}} d x

\int_{0}^{\frac{π}{2}} sin (θ) d θ

\int_{1}^{2} \frac{1}{x ln ( x )} d x

\int_{2}^{0} e^{x^{2} - x} d x

\int_{0}^{1} (2 x + 1)^{2} d x

What is the integral from pi/6 to pi of sin(w) ?
The integral from pi/6 to pi of sin(w) is 1+(sqrt(3))/2