What is the integral from 0 to y of 1/y ?

The integral from 0 to y of 1/y is diverges

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integral from 0 to y of 1/y

\int_{0}^{y} \frac{1}{y} d y

diverges

Solution steps

\int_{0}^{y} \frac{1}{y} d y

Use the common integral:

\int \frac{1}{y} d y = ln (∣ y ∣)

= [ln ∣ y ∣]_{0}^{y}

Compute the boundaries:

diverges

= diverges

\int_{0}^{3} x^{3} 81 - x^{4} d x

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\int_{1}^{2} \frac{x ^{2} + 2 x + 4}{x} d x

\int_{- 5}^{5} \frac{x ^{5}}{x ^{2} + 4} d x

\int_{0}^{1} 2 y d y

What is the integral from 0 to y of 1/y ?
The integral from 0 to y of 1/y is diverges