What is the integral from 1 to 4 of sqrt(u) ?

The integral from 1 to 4 of sqrt(u) is 14/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 4 of sqrt(u)

\int_{1}^{4} u d u

\frac{14}{3}

Decimal

4.66666 \dots

Solution steps

\int_{1}^{4} u d u

Apply the Power Rule

: [\frac{2}{3} u^{\frac{3}{2}}]_{1}^{4}

= [\frac{2}{3} u^{\frac{3}{2}}]_{1}^{4}

Compute the boundaries:

\frac{14}{3}

= \frac{14}{3}

\int_{0}^{1} x^{4} (1 + 2 x^{5})^{5} d x

\int_{- 1}^{0} - x d x

\int_{0}^{x} f (t) sin (x - t) d t

\int_{- 1}^{8} 1 + x d x

\int_{0}^{3} x d x

What is the integral from 1 to 4 of sqrt(u) ?
The integral from 1 to 4 of sqrt(u) is 14/3