What is the integral from 0 to 4 of xsqrt(x^2+10) ?

The integral from 0 to 4 of xsqrt(x^2+10) is (26sqrt(26)-10sqrt(10))/3

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integral from 0 to 4 of xsqrt(x^2+10)

\int_{0}^{4} x x^{2} + 10 d x

\frac{26 26 - 10 10}{3}

Decimal

33.65057 \dots

Solution steps

\int_{0}^{4} x x^{2} + 10 d x

Apply u-substitution

: \int_{10}^{26} u^{2} d u

= \int_{10}^{26} u^{2} d u

Apply the Power Rule

: [\frac{u ^{3}}{3}]_{10}^{26}

= [\frac{u ^{3}}{3}]_{10}^{26}

Compute the boundaries:

\frac{26 26 - 10 10}{3}

= \frac{26 26 - 10 10}{3}

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What is the integral from 0 to 4 of xsqrt(x^2+10) ?
The integral from 0 to 4 of xsqrt(x^2+10) is (26sqrt(26)-10sqrt(10))/3