What is the integral from-infinity to 0 of x/(e^x) ?

The integral from-infinity to 0 of x/(e^x) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-infinity to 0 of x/(e^x)

\int_{- \infty}^{0} \frac{x}{e ^{x}} d x

diverges

Solution steps

\int_{- \infty}^{0} \frac{x}{e ^{x}} d x

Compute the indefinite integral:

\int \frac{x}{e ^{x}} d x = - \frac{x}{e ^{x}} - \frac{1}{e ^{x}} + C

Compute the boundaries:

\int_{- \infty}^{0} \frac{x}{e ^{x}} d x =

diverges

= diverges

\int_{1}^{4} \frac{1}{( x - 2 ) ^{\frac{2}{3}}} d x

\int_{0}^{4} (4 - x^{2}) d x

\int_{0}^{t} e^{x} d x

\int_{0}^{\frac{π}{2}} cos (x^{2}) d x

\int_{3}^{4} ln (x) d x

What is the integral from-infinity to 0 of x/(e^x) ?
The integral from-infinity to 0 of x/(e^x) is diverges