What is the integral from-infinity to-3 of e^{-2x} ?

The integral from-infinity to-3 of e^{-2x} is diverges

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integral from-infinity to-3 of e^{-2x}

\int_{- \infty}^{- 3} e^{- 2 x} d x

diverges

Solution steps

\int_{- \infty}^{- 3} e^{- 2 x} d x

Compute the indefinite integral:

\int e^{- 2 x} d x = - \frac{1}{2} e^{- 2 x} + C

Compute the boundaries:

\int_{- \infty}^{- 3} e^{- 2 x} d x =

diverges

= diverges

\int_{- 2}^{4} x^{3} - 4 x^{2} + 3 x d x

\int_{0}^{1} \frac{e ^{x}}{e ^{2 x} + 1} d x

\int_{0}^{1} x^{2} x^{3} + 3 d x

\int_{- 1}^{1} 3 x^{2} d x

\int_{0}^{π} sin (t) cos (n t) d t

What is the integral from-infinity to-3 of e^{-2x} ?
The integral from-infinity to-3 of e^{-2x} is diverges