What is the integral from 0 to 8 of x^{2/3} ?

The integral from 0 to 8 of x^{2/3} is 96/5

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integral from 0 to 8 of x^{2/3}

\int_{0}^{8} x^{\frac{2}{3}} d x

\frac{96}{5}

Decimal Notation

19.2

Solution steps

\int_{0}^{8} x^{\frac{2}{3}} d x

Apply the Power Rule

: [\frac{3}{5} x^{\frac{5}{3}}]_{0}^{8}

= [\frac{3}{5} x^{\frac{5}{3}}]_{0}^{8}

Compute the boundaries:

\frac{96}{5}

= \frac{96}{5}

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What is the integral from 0 to 8 of x^{2/3} ?
The integral from 0 to 8 of x^{2/3} is 96/5