What is the integral from 0 to 2pi of (cos(x)) ?

The integral from 0 to 2pi of (cos(x)) is 0

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integral from 0 to 2pi of (cos(x))

\int_{0}^{2 π} (cos (x)) d x

0

Solution steps

\int_{0}^{2 π} cos (x) d x

Use the common integral:

\int cos (x) d x = sin (x)

= [sin (x)]_{0}^{2 π}

Compute the boundaries:

0

= 0

\int_{1}^{x} x^{2} d x

\int_{\frac{π}{4}}^{\frac{π}{2}} \frac{sin ( x )}{x} d x

\int_{- 4}^{4} - \frac{1}{5} x^{3} + 5 x d x

\int_{1}^{2} e^{2 x} d x

\int_{1}^{5} 1 + \frac{1}{u} + \frac{1}{u ^{2}} d u

What is the integral from 0 to 2pi of (cos(x)) ?
The integral from 0 to 2pi of (cos(x)) is 0