What is the integral from 1 to 2 of 1/(sqrt(x)) ?

The integral from 1 to 2 of 1/(sqrt(x)) is 2sqrt(2)-2

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integral from 1 to 2 of 1/(sqrt(x))

\int_{1}^{2} \frac{1}{x} d x

22 - 2

Decimal Notation

0.82842 \dots

Solution steps

\int_{1}^{2} \frac{1}{x} d x

Apply the Power Rule

: [2 x^{\frac{1}{2}}]_{1}^{2}

= [2 x^{\frac{1}{2}}]_{1}^{2}

Apply radical rule:

= [2 x]_{1}^{2}

Compute the boundaries:

22 - 2

= 22 - 2

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What is the integral from 1 to 2 of 1/(sqrt(x)) ?
The integral from 1 to 2 of 1/(sqrt(x)) is 2sqrt(2)-2