What is the integral from-5 to 1 of (x^2+4x-5) ?

The integral from-5 to 1 of (x^2+4x-5) is -36

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integral from-5 to 1 of (x^2+4x-5)

\int_{- 5}^{1} (x^{2} + 4 x - 5) d x

- 36

Solution steps

\int_{- 5}^{1} x^{2} + 4 x - 5 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 5}^{1} x^{2} d x + \int_{- 5}^{1} 4 x d x - \int_{- 5}^{1} 5 d x

\int_{- 5}^{1} x^{2} d x = 42

\int_{- 5}^{1} 4 x d x = - 48

\int_{- 5}^{1} 5 d x = 30

= 42 - 48 - 30

Simplify

= - 36

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What is the integral from-5 to 1 of (x^2+4x-5) ?
The integral from-5 to 1 of (x^2+4x-5) is -36