What is the integral from 8 to 27 of \sqrt[3]{x} ?

The integral from 8 to 27 of \sqrt[3]{x} is 195/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 8 to 27 of \sqrt[3]{x}

\frac{195}{4}

Decimal Notation

48.75

Solution steps

Apply the Power Rule

: [\frac{3}{4} x^{\frac{4}{3}}]_{8}^{27}

= [\frac{3}{4} x^{\frac{4}{3}}]_{8}^{27}

Compute the boundaries:

\frac{195}{4}

= \frac{195}{4}

\int_{0}^{1} \frac{1}{y} d y

\int_{- 1}^{5} ∣ x ∣ d x

\int_{0}^{1} \frac{2}{5} (2 x + 3 y) d y

\int_{- 2}^{3} x^{2} d x

\int_{0}^{2} t e^{- s t} d t

What is the integral from 8 to 27 of \sqrt[3]{x} ?
The integral from 8 to 27 of \sqrt[3]{x} is 195/4