What is the integral from 1 to 6 of 1/(x^2) ?

The integral from 1 to 6 of 1/(x^2) is 5/6

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integral from 1 to 6 of 1/(x^2)

\int_{1}^{6} \frac{1}{x ^{2}} d x

\frac{5}{6}

Decimal Notation

0.83333 \dots

Solution steps

\int_{1}^{6} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{1}^{6}

= [- \frac{1}{x}]_{1}^{6}

Compute the boundaries:

\frac{5}{6}

= \frac{5}{6}

\int_{- 1}^{0} x + 1 d x

\int_{1}^{3} ∣ x - 2 ∣ d x

\int_{1}^{\infty} cos (x) d x

\int_{- 4}^{1} (x^{2} + 3 x - 4) d x

\int_{0}^{1} x^{3} e^{2 x} d x

What is the integral from 1 to 6 of 1/(x^2) ?
The integral from 1 to 6 of 1/(x^2) is 5/6