What is the integral from 0 to x^2 of 3sin(t) ?

The integral from 0 to x^2 of 3sin(t) is 3(-cos(x^2)+1)

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integral from 0 to x^2 of 3sin(t)

\int_{0}^{x^{2}} 3 sin (t) d t

3 (- cos (x^{2}) + 1)

Solution steps

\int_{0}^{x^{2}} 3 sin (t) d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{0}^{x^{2}} sin (t) d t

Use the common integral:

\int sin (t) d t = - cos (t)

= 3 [- cos (t)]_{0}^{x^{2}}

Compute the boundaries:

- cos (x^{2}) + 1

= 3 (- cos (x^{2}) + 1)

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What is the integral from 0 to x^2 of 3sin(t) ?
The integral from 0 to x^2 of 3sin(t) is 3(-cos(x^2)+1)