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Popular >

integral from 0 to 5 of (x^2+1)

Solution

\int_{0}^{5} (x^{2} + 1) d x

Solution

\frac{140}{3}

+1

Decimal Notation

46.66666 \dots

Solution steps

\int_{0}^{5} x^{2} + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{5} x^{2} d x + \int_{0}^{5} 1 d x

\int_{0}^{5} x^{2} d x = \frac{125}{3}

\int_{0}^{5} 1 d x = 5

= \frac{125}{3} + 5

Simplify

\frac{125}{3} + 5 : \frac{140}{3}

= \frac{140}{3}

Popular Examples

integral from 2 to 8 of x^2

\int_{2}^{8} x^{2} d x

integral from 0 to 1 of x^5sqrt(1-x^6)

\int_{0}^{1} x^{5} 1 - x^{6} d x

integral from-1 to 2 of 4-x^2

\int_{- 1}^{2} 4 - x^{2} d x

integral from 0 to pi of (sin(x)-8)

\int_{0}^{π} (sin (x) - 8) d x

integral from 0 to pi/2 of 9cos^2(θ)

\int_{0}^{\frac{π}{2}} 9 cos^{2} (θ) d θ

Frequently Asked Questions (FAQ)

What is the integral from 0 to 5 of (x^2+1) ?
The integral from 0 to 5 of (x^2+1) is 140/3