What is the integral from 1 to 2 of tan(x)y ?

The integral from 1 to 2 of tan(x)y is tan(x) 3/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 2 of tan(x)y

\int_{1}^{2} tan (x) y d y

tan (x) \frac{3}{2}

Solution steps

\int_{1}^{2} tan (x) y d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= tan (x) \cdot \int_{1}^{2} y d y

Apply the Power Rule

: [\frac{y ^{2}}{2}]_{1}^{2}

= tan (x) [\frac{y ^{2}}{2}]_{1}^{2}

Compute the boundaries:

\frac{3}{2}

= tan (x) \frac{3}{2}

\int_{0}^{a} x^{2} d x

\int_{- 1}^{4} \frac{2}{3 x ^{2}} d x

\int_{1}^{- 1} (12 r + 11)^{2} d r

\int_{- 1}^{0} \frac{1}{x ^{2} - 4} d x

\int_{0}^{2} - t^{2} + 3 t - 2 d t

What is the integral from 1 to 2 of tan(x)y ?
The integral from 1 to 2 of tan(x)y is tan(x) 3/2