What is the integral from 0 to 1-x of 2 ?

The integral from 0 to 1-x of 2 is 2(-x+1)

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integral from 0 to 1-x of 2

\int_{0}^{1 - x} 2 d y

2 (- x + 1)

Solution steps

\int_{0}^{1 - x} 2 d y

Integral of a constant:

\int a d x = a x

= [2 y]_{0}^{1 - x}

Compute the boundaries:

2 (- x + 1)

= 2 (- x + 1)

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\int_{0}^{1} \frac{1}{( 1 + x ^{2} )} d x

\int_{0}^{8} \frac{1}{x ^{2} + 64} d x

\int_{0}^{t} e^{- t} d t

\int_{6}^{11} 4 - 10 e^{- 0.2 x} d x

What is the integral from 0 to 1-x of 2 ?
The integral from 0 to 1-x of 2 is 2(-x+1)