What is the integral from 0 to 11/12 of 20x ?

The integral from 0 to 11/12 of 20x is 605/72

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integral from 0 to 11/12 of 20x

\int_{0}^{\frac{11}{12}} 20 x d x

\frac{605}{72}

Decimal Notation

8.40277 \dots

Solution steps

\int_{0}^{\frac{11}{12}} 20 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 20 \cdot \int_{0}^{\frac{11}{12}} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{\frac{11}{12}}

= 20 [\frac{x ^{2}}{2}]_{0}^{\frac{11}{12}}

Compute the boundaries:

\frac{121}{288}

= 20 \cdot \frac{121}{288}

Simplify

= \frac{605}{72}

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What is the integral from 0 to 11/12 of 20x ?
The integral from 0 to 11/12 of 20x is 605/72