What is the integral from 0 to pi/4 of sec^2(θ) ?

The integral from 0 to pi/4 of sec^2(θ) is 1

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integral from 0 to pi/4 of sec^2(θ)

\int_{0}^{\frac{π}{4}} sec^{2} (θ) d θ

1

Solution steps

\int_{0}^{\frac{π}{4}} sec^{2} (θ) d θ

Use the common integral:

\int sec^{2} (θ) d θ = tan (θ)

= [tan (θ)]_{0}^{\frac{π}{4}}

Compute the boundaries:

1

= 1

\int_{1}^{5} (5 - x)^{2} d x

\int_{- 2}^{- 1} x d x

\int_{0}^{y} e^{- y^{2}} d y

\int_{0}^{π} x^{2} sin (3 x) d x

\int_{0}^{2} t d t

What is the integral from 0 to pi/4 of sec^2(θ) ?
The integral from 0 to pi/4 of sec^2(θ) is 1