What is the integral from-1 to 1 of (e^x-e^{-x}) ?

The integral from-1 to 1 of (e^x-e^{-x}) is 0

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integral from-1 to 1 of (e^x-e^{-x})

\int_{- 1}^{1} (e^{x} - e^{- x}) d x

0

Solution steps

\int_{- 1}^{1} e^{x} - e^{- x} d x

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

e^{x} - e^{- x} :

Odd

= 0

\int_{0}^{2} x^{2} - x d x

\int_{x}^{x + 2} \frac{1}{24} (x + y) d y

\int_{0}^{1} (x^{2} + 2) e^{4 x} d x

\int_{0}^{π} 1 + cos (x) d x

\int_{0}^{0.5} e^{- x^{2}} d x

What is the integral from-1 to 1 of (e^x-e^{-x}) ?
The integral from-1 to 1 of (e^x-e^{-x}) is 0