What is the integral from 2 to 7 of 1/x ?

The integral from 2 to 7 of 1/x is ln(7)-ln(2)

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integral from 2 to 7 of 1/x

\int_{2}^{7} \frac{1}{x} d x

ln (7) - ln (2)

Decimal Notation

1.25276 \dots

Solution steps

\int_{2}^{7} \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= [ln ∣ x ∣]_{2}^{7}

Compute the boundaries:

ln (7) - ln (2)

= ln (7) - ln (2)

\int_{- 1}^{1} (4 x^{3} - 6 x^{2} + 2 x - 1) d x

\int_{\frac{π}{2}}^{\frac{3 π}{4}} sin (x) d x

\int_{0}^{\frac{π}{2}} sin (t) cos (t) d t

\int_{0}^{3} - 2 x^{2} + 6 x d x

\int_{0}^{x^{3}} sin (t^{2}) d t

What is the integral from 2 to 7 of 1/x ?
The integral from 2 to 7 of 1/x is ln(7)-ln(2)